This tutor brings a wealth of experience in language education, having spent over three years teaching English to young learners abroad. With a strong focus on planning and conducting engaging lessons, this tutor has demonstrated exceptional ability to adapt teaching methods to suit the educational needs of students. Their background also includes promoting educational programs, showcasing their capability to inspire and attract interest in learning.
Possessing an impressive range of qualifications, this tutor is currently pursuing a Bachelor of Clinical Chiropractic while holding diplomas and certifications in remedial massage and programming. Their academic journey also includes studies in fine arts and architecture, equipping them with diverse skills that enrich their tutoring approach. This broad educational foundation enables them to assist students in various subjects with creativity and precision.
This tutor is not only dedicated to academic excellence but also prioritizes the well-being of their students. Holding necessary clearances for working with children, they offer a safe and supportive learning environment. They are flexible, living conveniently near a local high school which makes them readily available for tutoring sessions tailored to fit student schedules. Their approach is patient and accommodating, ideal for students needing extra support in their studies.
Recent Tutoring Comments:
Thanks for the great year. I'll see you guys next year
Thanks for the great year. I'll see you guys next year
Catch you next year
I feel like Tom's understanding is there.
I feel like Tom's understanding is there.
May require a little extra effort to ensure he remembers all the concepts come the exam. I am sure he can do it.
James is a great student who demonstrates great problem solving skills and a strong grasp of mathematical concepts.
James is a great student who demonstrates great problem solving skills and a strong grasp of mathematical concepts.
nothing to add at this time
y=mx+c most part really good, just a little improvement with >>>
y=mx+c most part really good, just a little improvement with >>>
finding y intercept. find the amount that x-shifts from one point to the next, and using this to calculate y=0